The maximum number of triangles in graphs without large linear forests

Research paper by Xiuzhuan Duan, Jian Wang, Weihua Yang

Indexed on: 21 Dec '18Published on: 21 Dec '18Published in: arXiv - Mathematics - Combinatorics


Let $G$ be a graph on $n$ vertices. A linear forest is a graph consisting of vertex-disjoint paths and isolated vertices. A maximum linear forest of $G$ is a subgraph of $G$ with maximum number of edges, which is a linear forest. We denote by $l(G)$ this maximum number. Let $t=\left\lfloor (k-1)/2\right \rfloor$. Recently, Ning and Wang \cite{boning} proved that if $l(G)=k-1$, then for any $k<n$ \[ e(G) \leq \max \left\{\binom{k}{2},\binom{t}{2}+t (n - t)+ c \right\}, \] where $c=0$ if $k$ is odd and $c=1$ otherwise, and the inequality is tight. In this paper, we prove that if $l(G)=k-1$ and $\delta(G)=\delta$ ($\delta<\lfloor k/2 \rfloor$), then for any $k<n$ \[ e(G) \leq \max \left\{\binom{k-\delta}{2}+\delta(n-k+\delta),\binom{t}{2}+t\left(n-t\right)+c \right\}. \] When $\delta=0$, it reduces to Ning and Wang's result. Moreover, let $r_3(G)$ be the number of triangles in $G$. We prove that if $l(G)=k-1$ and $\delta(G)= \delta$, then for any $k<n$ \[ r_3(G)\leq \max \left\{\binom{k-\delta}{3}+\binom{\delta}{2}(n-k+\delta),\binom{t}{3}+\binom{t}{2}\left(n-t\right)+d \right\}. \] where $d=0$ if $k$ is odd and $d=t$ otherwise.